×
Well done. You've clicked the tower. This would actually achieve something if you had logged in first. Use the key for that. The name takes you home. This is where all the applicables sit. And you can't apply any changes to my site unless you are logged in.

Our policy is best summarized as "we don't care about _you_, we care about _them_", no emails, so no forgetting your password. You have no rights. It's like you don't even exist. If you publish material, I reserve the right to remove it, or use it myself.

Don't impersonate. Don't name someone involuntarily. You can lose everything if you cross the line, and no, I won't cancel your automatic payments first, so you'll have to do it the hard way. See how serious this sounds? That's how serious you're meant to take these.

×
Register


Required. 150 characters or fewer. Letters, digits and @/./+/-/_ only.
  • Your password can’t be too similar to your other personal information.
  • Your password must contain at least 8 characters.
  • Your password can’t be a commonly used password.
  • Your password can’t be entirely numeric.

Enter the same password as before, for verification.
Login

Grow A Dic
Define A Word
Make Space
Set Task
Mark Post
Apply Votestyle
Create Votes
(From: saved spaces)
Exclude Votes
Apply Dic
Exclude Dic

Click here to flash read.

The $2$-adic complexity has been well-analyzed in the periodic case. However,
we are not aware of any theoretical results on the $N$th $2$-adic complexity of
any promising candidate for a pseudorandom sequence of finite length $N$ or
results on a part of the period of length $N$ of a periodic sequence,
respectively. Here we introduce the first method for this aperiodic case. More
precisely, we study the relation between $N$th maximum-order complexity and
$N$th $2$-adic complexity of binary sequences and prove a lower bound on the
$N$th $2$-adic complexity in terms of the $N$th maximum-order complexity. Then
any known lower bound on the $N$th maximum-order complexity implies a lower
bound on the $N$th $2$-adic complexity of the same order of magnitude. In the
periodic case, one can prove a slightly better result. The latter bound is
sharp which is illustrated by the maximum-order complexity of $\ell$-sequences.
The idea of the proof helps us to characterize the maximum-order complexity of
periodic sequences in terms of the unique rational number defined by the
sequence. We also show that a periodic sequence of maximal maximum-order
complexity must be also of maximal $2$-adic complexity.

Click here to read this post out
ID: 424503; Unique Viewers: 0
Unique Voters: 0
Total Votes: 0
Votes:
Latest Change: Sept. 25, 2023, 7:31 a.m. Changes:
Dictionaries:
Words:
Spaces:
Views: 10
CC:
No creative common's license
Comments: